Sum of two numbers using C, C++ & Java

 To find the sum of two numbers using C, C++ & Java we have two ways :-

1. Hardcode values in the code.

2. Take input from user.

1. Hardcode values in the code using C.

#include<stdio.h>

int main()

{

    int n1=2,n2=3,sum=0;

    sum=n1+n2;

    printf("The sum of 2 number is : %d ",s);

    return 0;

}

1. Hardcode values in the code using C++.

#include <iostream>

using namespace std;

int main()

{

    int n1=2,n2=3,sum=0;

    

    sum = a+b;

    cout<<"\nThe sum of two numbers  : "<<sum;

    return 0;

}

1. Hardcode values in the code using Java.

public class SumOfNumbers1  

{  

    public static void main(String args[])   

    {  

        int n1 = 2, n2 = 3, sum;  

        sum = n1 + n2;  

        System.out.println("The sum of two numbers is: "+sum);  

    }  

}  

2. Take input from user using C

#include<stdio.h>

int main()

{

    int n1,n2,sum=0;

    printf("Enter 2 Number : ");

    scanf("%d%d",&n1,&n2);

    sum=n1+n2;

    printf("The Sum of two number : %d ",sum);

    return 0;

}

2. Take input from user using C++

#include <iostream>

using namespace std;

int main()

{

    int n1, n2, sum=0;

    cout<<"Enter any two numbers : ";

    cin>>n1>>n2;

    sum = n1+ n2;

    

    cout<<"\nSum of 1st three numbers   : "<<sum;

    return 0;

}

2. Take input from user using Java

import java.util.Scanner;  

public class SumOfNumbers2  

{  

    public static void main(String args[])  

    {  

        int n1, n2, sum=0;  

        Scanner sc = new Scanner(System.in);  

        System.out.print("Enter the first number: ");  

        n1 = sc.nextInt();  

        System.out.print("Enter the second number: ");  

        n2 = sc.nextInt();  

        sum = n1+n2; 

        System.out.println("The sum of two numbers n1 and n2 is: " + sum);  

    }  

}